BASH variable inside AWK that is itself an AWK command

Hi. I want to use a BASH variable inside AWK that is an AWK command. Here is my test code that I plan to make more complicated if I can find a solution to this problem.

exptransform=(
    'print "test"'
)
awk -v awk_exptransform="${exptransform}" '                                                                                                                                                  
    BEGIN{                                                                                                                                                                                   
        printf ("Test.n")                                                                                                                                                                   
        printf ("This is another test: %sn",awk_exptransform)                                                                                                                               
        awk_exptransform                                                                                                                                                                     
    }                                                                                                                                                                                        
'

This gives successful output for the first two lines in the begin statement. The third line returns nothing. How do I get AWK to execute the contents of the variable as a command?

I have done many searches on the Internet and on this site with a variety of search terms. I have read the relevant section of sed & awk (Dougherty, & Robbins, 1997). What am I missing? Is this possible?

Sincerely,

Dante Picchioni